题目传送门:http://acm.hdu.edu.cn/showproblem.php?pid=1026
题目大意:一个人要从N*M矩形地图的左上角走到右下角.且只能向四个方向走.X表示墙不能走.字符1-9表示怪物并且数字代表怪物的血量.也就是杀死怪物需要该数字的单位时间.人每走一个格子花费1个单位的时间.然后要你按照格式打印最短时间的路径和具体的路径.
简单的最短路径题.直接用bfs做.用二维数组保存路径.由终点往起点递归.就可以把完整的顺序路径加到容器中去.
AC代码:
#include <iostream>
#include <set>
#include <map>
#include <queue>
#include <string>
#include <vector>
#include <stdio.h>
#include <math.h>
#include <memory.h>
#include <functional>
#include <algorithm>
using namespace std;
#define Size 200
typedef std::pair<int, int> pairType;
struct Node
{
int x;
int y;
int time;
//时间优先.
bool operator<(Node a) const
{
return this->time> a.time;
}
};
int dir[4][2] = { { 0, 1 }, { 1, 0 }, { 0, -1 }, { -1, 0 } };
char world[Size][Size];
int visit[Size][Size];
Node path[Size][Size];
int m, n;
char cr;
vector<pairType> filePath;
int num;
void advisitath(int x,int y)
{
//判断是否到起始点.
if (x == 0 && y == 0)
{
return;
}
advisitath(path[x][y].x, path[x][y].y);
//因为是递归.最好其实是顺序加入路径的.
filePath.push_back(pairType(path[x][y].x, path[x][y].y));
}
void print()
{
//把路径加到容器中.
advisitath(m - 1, n - 1);
filePath.push_back(pairType(m - 1, n - 1));
int secNum = 1;
printf("It takes %d seconds to reach the target position, let me show you the way.\n", num);
for (int i = 0; i < filePath.size() - 1; ++i)
{
printf("%ds:(%d,%d)->(%d,%d)\n", secNum++, filePath[i].first, filePath[i].second, filePath[i + 1].first, filePath[i + 1].second);
//如果不是正常路.也就是怪物.
if (world[filePath[i+1].first][filePath[i+1].second] != '.')
{
for (int j = 0; j < world[filePath[i+1].first][filePath[i+1].second] - '0'; ++j)
{
printf("%ds:FIGHT AT (%d,%d)\n", secNum++, filePath[i+1].first, filePath[i+1].second);
}
}
}
printf("FINISH\n");
filePath.clear();
}
int bfs()
{
//题目要求最短时间.以时间优先即可.
priority_queue<Node> temp;
Node now, next, s;
memset(&s, 0, sizeof(s));
temp.push(s);
visit[0][0] = 1;
while (!temp.empty())
{
now = temp.top();
temp.pop();
//判断是否到达.
if (now.x == m - 1 && now.y == n - 1)
{
return now.time;
}
//分别枚举四个方向.
for (int i = 0; i < 4; ++i)
{
next.x = now.x + dir[i][0];
next.y = now.y + dir[i][1];
//进行筛选.
if (next.x >= 0 && next.y >= 0 && next.x < m && next.y < n && visit[next.x][next.y] == 0 && world[next.x][next.y] != 'X')
{
visit[next.x][next.y] = 1;
//记录来的路径.
path[next.x][next.y].x = now.x;
path[next.x][next.y].y = now.y;
if (world[next.x][next.y] == '.')
{
//普通路+1.
next.time = now.time + 1;
}
else
{
//遇到怪物.先+1.然后再加怪物的血量.记得读取的是字符.
next.time = now.time + world[next.x][next.y] - '0' + 1;
}
temp.push(next);
}
}
}
return -1;
}
int main()
{
while (scanf("%d%d", &m,&n) != EOF)
{
for (int i = 0; i < m; ++i)
{
//要先用getchar()把换行符读取掉.
getchar();
for (int j = 0; j < n; ++j)
{
scanf("%c", &world[i][j]);
visit[i][j] = 0;
}
}
memset(path, 0, sizeof(path));
num = bfs();
if (num == -1)
{
printf("God please help our poor hero.\n");
printf("FINISH\n");
}
else
{
print();
}
}
return 0;
}