Problem D: 字符类的封装_要输入一个文字符类型,要如何封装-优快云博客

本文介绍了一个简单的字符类封装练习，包括无参构造函数、构造函数、设置和获取字符及ASCII码的方法。通过示例展示了如何使用这个类。

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Problem D: 字符类的封装

Time Limit: 1 Sec Memory Limit: 128 MB
Submit: 1078 Solved: 808
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Description

先来个简单习题，练练手吧！现在需要你来编写一个Character类，将char这一基本数据类型进行封装。该类中需要有如下成员函数：

1. 无参构造函数。

2. 构造函数Character(char)：用参数初始化数据成员。

3. void setCharacter(char)：重新设置字符值。

4. int getAsciiCode()：返回字符的ASII码。

5. char getCharacter()：返回字符值。

6. 析构函数。

Input

输入只有1行，包含一个合法的、可打印的字符。

Output

输出有好多行，请参考样例来编写相应的函数。

Sample Input

Sample Output

Default constructor is called!Character a is created!ch1 is c and its ASCII code is 99.ch2 is a and its ASCII code is 97.Character a is erased!Character c is erased!

HINT

Append Code

append.cc,

#include <iostream>
using namespace std;
class Character
{
private:
    char c;
public:
    Character()
    {
        cout<<"Default constructor is called!"<<endl;
    }
    Character(char s)
    {
        cout<<"Character "<<s<<" is created!"<<endl;
        c = s;
    }
    void setCharacter(char x)
    {
        c = x;
    }
    int getAsciiCode(){return c;}
    char getCharacter(){return c;}
    ~Character()
    {
        cout<<"Character "<<c<<" is erased!"<<endl;
    }
};
int main()
{
    char ch;
    Character ch1, ch2('a');
    cin>>ch;
    ch1.setCharacter(ch);
    cout<<"ch1 is "<<ch1.getCharacter()<<" and its ASCII code is "<<ch1.getAsciiCode()<<"."<<endl;
    cout<<"ch2 is "<<ch2.getCharacter()<<" and its ASCII code is "<<ch2.getAsciiCode()<<"."<<endl;
    return 0;
}