from表单使用ajax异步提交

//js代码

function saveReport() {
    var getName=$("#getName").val();
    $.ajax({
        type: "POST",
        url: ,
        data : {name:getName},
        success: function(msg) {
            alert("提交成功");
        }
    });
    return false;
}   
//jsp代码

<form i  onsubmit="return saveReport();" >  

          <input type="text" class="input w50"  id="getName" value="" name="name"  />

          <button class="button bg-main icon-check-square-o"  type="submit"  >提交</button>

    </form>