直接上代码,可直接运行:
public static void main(String[] args) {
List<Map<String, Object>> list = new ArrayList<Map<String, Object>>();
Map<String, Object> map1 = new HashMap<String, Object>();
map1.put("id", 1);
map1.put("date", 20190425);
map1.put("value", 2);
list.add(map1);
Map<String, Object> map2 = new HashMap<String, Object>();
map2.put("id", 1);
map2.put("date", 20190425);
map2.put("value", 5);
list.add(map2);
Map<String, Object> map3 = new HashMap<String, Object>();
map3.put("id", 2);
map3.put("date", 20190425);
map3.put("value", 5);
list.add(map3);
Map<String, Object> map4 = new HashMap<String, Object>();
map4.put("id", 2);
map4.put("date", 20190425);
map4.put("value", 4);
list.add(map4);
Map<String, Object> map5 = new HashMap<String, Object>();
map5.put("id", 1);
map5.put("date", 20190424);
map5.put("value", 4);
list.add(map5);
//id相等value相加(合并id相同数据)
System.out.println("原始数据:"+list);
//方法二
Map<String, Map<String, Object>> result = new HashMap<String, Map<String,Object>>();
List<Map<String, Object>> allList = new ArrayList<>();
for(Map<String, Object> map : list){
String id = map.get("id").toString();
String date = map.get("date").toString();
String newId = id+date;
Long value = Long.parseLong(map.get("value").toString());
if(result.containsKey(newId)){
Long temp = Long.parseLong(result.get(newId).get("value").toString());
value += temp;
result.get(newId).put("value", value);
continue;
}
result.put(newId, map);
allList.add(map);
}
System.out.println("合并后的数据2:"+allList);
}
根据date和id相等的key相加求和,效果如下:

本文提供了一段Java代码示例,展示了如何处理包含ID、日期和值的Map集合,通过合并具有相同ID和日期的记录并对其值进行求和,实现了数据的高效聚合。
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