问题描述
给定当前的时间,请用英文的读法将它读出来。
时间用时h和分m表示,在英文的读法中,读一个时间的方法是:
如果m为0,则将时读出来,然后加上“o'clock”,如3:00读作“three o'clock”。
如果m不为0,则将时读出来,然后将分读出来,如5:30读作“five thirty”。
时和分的读法使用的是英文数字的读法,其中0~20读作:
0:zero, 1: one, 2:two, 3:three, 4:four, 5:five, 6:six, 7:seven, 8:eight, 9:nine, 10:ten, 11:eleven, 12:twelve, 13:thirteen, 14:fourteen, 15:fifteen, 16:sixteen, 17:seventeen, 18:eighteen, 19:nineteen, 20:twenty。
30读作thirty,40读作forty,50读作fifty。
对于大于20小于60的数字,首先读整十的数,然后再加上个位数。如31首先读30再加1的读法,读作“thirty one”。
按上面的规则21:54读作“twenty one fifty four”,9:07读作“nine seven”,0:15读作“zero fifteen”。
输入格式
输入包含两个非负整数h和m,表示时间的时和分。非零的数字前没有前导0。h小于24,m小于60。
输出格式
输出时间时刻的英文。
样例输入
0 15
样例输出
zero fifteen
枚举,又臭又长的,没有自行车,列就完了o( ̄ヘ ̄o#)
#include<cstdio>
void printM(int x){
int m=x;
switch(m){
case 0 :{printf("o'clock");break;}
case 1 :{printf("one");break;}
case 2 :{printf("two");break;}
case 3 :{printf("three");break;}
case 4 :{printf("four");break;}
case 5 :{printf("five"); break;}
case 6 :{printf("six");break;}
case 7 :{printf("seven");break;}
case 8 :{printf("eight");break;}
case 9 :{printf("nine");break;}
case 10 :{printf("ten");break;}
case 11 :{printf("eleven");break;}
case 12 :{printf("twelve");break;}
case 13 :{printf("thirteen");break;}
case 14 :{printf("fourteen");break;}
case 15 :{printf("fifteen");break;}
case 16 :{printf("sixteen");break;}
case 17 :{printf("seventeen");break;}
case 18 :{printf("eighteen");break;}
case 19 :{printf("nineteen");break;}
case 20 :{printf("twenty");break;}
case 30 :{printf("thirty");break;}
case 40 :{printf("forty");break;}
case 50 :{printf("fifty");break;}
default: {
int a,b;
a=m-m%10;
b=m%10;
printM(a);
printf(" ");
printM(b);
break;
}
}
}
int main(){
int h,m;
scanf("%d %d",&h,&m);
switch(h){
case 0 :{printf("zero "); break;}
case 1 :{printf("one "); break;}
case 2 :{printf("two ");break;}
case 3 :{printf("three "); break;}
case 4 :{printf("four ");break;}
case 5 :{printf("five "); break;}
case 6 :{printf("six ");break;}
case 7 :{printf("seven ");break;}
case 8 :{printf("eight ");break;}
case 9 :{printf("nine ");break;}
case 10 :{printf("ten ");break;}
case 11 :{printf("eleven ");break;}
case 12 :{printf("twelve ");break;}
case 13 :{printf("thirteen "); break;}
case 14 :{printf("fourteen "); break;}
case 15 :{printf("fifteen ");break;}
case 16 :{printf("sixteen "); break;}
case 17 :{printf("seventeen ");break;}
case 18 :{printf("eighteen "); break;}
case 19 :{printf("nineteen ");break;}
case 20 :{printf("twenty ");break;}
case 21 :{printf("twenty one ");break;}
case 22 :{printf("twenty two "); break;}
case 23 :{printf("twenty three ");break;}
default: break;
}
printM(m);
return 0;
}