首先构造一个html文本
let str =
`/*<div>
<h1>123</h1>
<h2>234</h2>
<h2>error</h3>
<H2>345</H2>
</div>>*/`
然后去除首位的/**/
let str =
`/*<div>
<h1>123</h1>
<h2>234</h2>
<h2>error</h3>
<H2>345</H2>
</div>*/`
let pat = /^\/\*([^]+)\*\/$/
let res = str.match(pat)[1]
console.log(res)
众所周知,<h2>只能与</h2>匹配,不能<H2>与</H3>匹配, 按照常规的配置方式,显然是做不到的,这里需要用到回溯引用
通过\1引用第一个子表达式的内容,接着改造代码
let str =
`/*<div>
<h1>123</h1>
<h2>234</h2>
<h2>error</h3>
<H2>345</H2>
</div>*/`
let pat = /^\/\*([^]+)\*\/$/
let res = str.match(pat)[1]
let pat1 = /<[hH]([1-6])>([^]*?)<\/[hH]\1>/
// console.log(res)
let dd = res.match(pat1)
console.log(dd)
//-------------控制台结果------------------
0: "<h1>123</h1>"
1: "1"
2: "123"
groups: undefined
index: 6
input: "<div>↵<h1>123</h1>↵<h2>234</h2>↵<h2>error</h3>↵<H2>345</H2>↵</div>"
另外同样H与h需要区分大小写,同样适用回溯,前后一致
let str =
`/*<div>
<h1>123</h1>
<h2>234</h2>
<h2>error</h3>
<H2>345</H2>
</div>*/`
let pat = /^\/\*([^]+)\*\/$/
let res = str.match(pat)[1]
let pat1 = /<([hH])([1-6])>([^]*?)<\/\1\2>/g
// console.log(res)
let dd = res.match(pat1)
console.log(dd)
此时把匹配改为全局匹配,看效果
//-----------控制台输出--------------
0: "<h1>123</h1>"
1: "<h2>234</h2>"
2: "<H2>345</H2>"
更我们想象的一致,后面再把数组再次提取 数据,就OK啦
先溜了溜了,太困了