[PAT甲级] 1001 A+B Format (20)

最新推荐文章于 2022-01-28 19:57:46 发布

原创最新推荐文章于 2022-01-28 19:57:46 发布 · 232 阅读

0 ·

CC 4.0 BY-SA版权

文章标签：

#PTA

PTA题解专栏收录该内容

10 篇文章

订阅专栏

本文介绍了一种简单的算法，用于计算两个整数的和，并将结果以标准格式输出，即使用逗号分隔每三位数字。算法首先读取两个整数a和b，计算它们的和，然后将和转换为字符串，最后遍历字符串并插入逗号以符合格式要求。

摘要生成于 C知道，由 DeepSeek-R1 满血版支持，前往体验 >

Calculate a + b and output the sum in standard format -- that is, the digits must be separated into groups of three by commas (unless there are less than four digits).

Input

Each input file contains one test case. Each case contains a pair of integers a and b where -1000000 <= a, b <= 1000000. The numbers are separated by a space.

Output

For each test case, you should output the sum of a and b in one line. The sum must be written in the standard format.

Sample Input

-1000000 9

Sample Output

-999,991

一个简单直观的解法如下：

#include <iostream>
#include <cstdio>
#include <cstring>
using namespace std;
int main()
{
    int a, b;
    cin >> a >> b;
    int sum = a + b;
    char res[9];
    sprintf(res, "%d", sum);
    int cnt = 0, len = strlen(res);
    cnt = len % 3;

    for(int i = 0; i < len; i ++)
    {
        cout << res[i];
        cnt --;
        if (cnt <= 0 && cnt % -3 == 0 && res[i] != '-' && i != len - 1)
        {
            cout << ",";
        }
    }
    return 0;
}