判断一个数是否为回文数

import java.util.Scanner;
public class Homework7
{
public static void main(String[] args)
{
System.out.println("请输入一个1-9999之间的数：");
Scanner input=new Scanner(System.in);
int n=input.nextInt();
int m=n;
if(n<1||n>9999)
{
System.out.println("输入错误！！");
}
else
{
int count=0;
while(m>1)
{
m=m/10;
count++;
}
System.out.println(n+"是"+count+("位数"));
switch (count)
{
case 1:
System.out.println(n+"不是回文数！");
break;
case 2:
int a=n/10;
int b=n%10;
if(a==b)
{
System.out.println(n+"是回文数！");
}
else
{
System.out.println(n+"不是回文数！");
}
break;
case 3:
int c=n/100;
int d=n%10;
if(d==c)
{
System.out.println(n+"是回文数！");
}
else
{
System.out.println(n+"不是回文数！");
}
break;
case 4:
int e=n/1000;
int f=(n%1000)/100;
int g=(n%100)/10;
int h=n%10;
if(e==h && f==g)
{
System.out.println(n+"是回文数！");
}
else
{
System.out.println(n+"不是回文数！");
}
break;
default:
break;
}
}
}


}