PAT 甲级 1002

1. A+B for Polynomials (25)
   作者
   CHEN, Yue

This time, you are supposed to find A+B where A and B are two polynomials.

Input

Each input file contains one test case. Each case occupies 2 lines, and each line contains the information of a polynomial: K N1 aN1 N2 aN2 … NK aNK, where K is the number of nonzero terms in the polynomial, Ni and aNi (i=1, 2, …, K) are the exponents and coefficients, respectively. It is given that 1 <= K <= 10，0 <= NK < … < N2 < N1 <=1000.

Output

For each test case you should output the sum of A and B in one line, with the same format as the input. Notice that there must be NO extra space at the end of each line. Please be accurate to 1 decimal place.

Sample Input
2 1 2.4 0 3.2
2 2 1.5 1 0.5
Sample Output
3 2 1.5 1 2.9 0 3.2

# 思路
# 用数组来表示多项式系数比较方便
# 需要注意的是，多项式相加后系数为0，则不再显示

poly = [0 for i in range(1002)] # 开一个数组
line_1 = input().split()
line_2 = input().split()
# 获得多项式长度
N1 = int(line_1[0])
N2 = int(line_2[0])
# 获得多项式信息
for i in range(N1):
    coefficient = float(line_1[1+2*i+1])
    exponent = int(line_1[1+2*i])
    poly[exponent] += coefficient

for i in range(N2):
    coefficient = float(line_2[1+2*i+1])
    exponent = int(line_2[1+2*i])
    poly[exponent] += coefficient

count = 0
result = ""
for i in range(len(poly)):
    if poly[i] != 0: # 忽视为0的项g
        count += 1
        coe = "%.1f" % poly[i] # python 答题一定要注意一位小数输出， 否则会错一个测试点
        result = ' ' + str(i) + ' ' + coe + result # 实现逆序输出

result = str(count) + result
print(result)