hdu 1019

The least common multiple (LCM) of a set of positive integers is the smallest positive integer which is divisible by all the numbers in the set. For example, the LCM of 5, 7 and 15 is 105. 

Input

Input will consist of multiple problem instances. The first line of the input will contain a single integer indicating the number of problem instances. Each instance will consist of a single line of the form m n1 n2 n3 ... nm where m is the number of integers in the set and n1 ... nm are the integers. All integers will be positive and lie within the range of a 32-bit integer. 

Output

For each problem instance, output a single line containing the corresponding LCM. All results will lie in the range of a 32-bit integer. 

Sample Input

2
3 5 7 15
6 4 10296 936 1287 792 1

Sample Output

10510296

代码是我偷来的，非常简洁，递归求解

#include <stdio.h>
#include <stdlib.h>
int gcd(int a,int b)
{
    if(b==0)
	return a;
    return gcd(b,a%b);
}
int main()
{
    int group;
    int n,a,b,i;
    int cnt;
    scanf("%u",&group);
    while(group--)
    {
        scanf("%d",&n);
        cnt=a=1;
        for(i=1;i<=n;i++)
        {
            scanf("%d",&b);
            cnt=a/gcd(a,b)*b;//换一下，先除后乘，免得数据溢出
            a=cnt;
        }
        printf("%d\n",cnt);
    }
    return 0;
}