IMMEDIATE DECODABILITY
Description
An encoding of a set of symbols is said to be immediately decodable if no code for one symbol is the prefix of a code for another symbol. We will assume for this problem that all codes are in binary, that no two codes within a set of codes are the same, that
each code has at least one bit and no more than ten bits, and that each set has at least two codes and no more than eight.
Examples: Assume an alphabet that has symbols {A, B, C, D}
The following code is immediately decodable:
A:01 B:10 C:0010 D:0000
but this one is not:
A:01 B:10 C:010 D:0000 (Note that A is a prefix of C)
Examples: Assume an alphabet that has symbols {A, B, C, D}
The following code is immediately decodable:
A:01 B:10 C:0010 D:0000
but this one is not:
A:01 B:10 C:010 D:0000 (Note that A is a prefix of C)
Input
Write a program that accepts as input a series of groups of records from standard input. Each record in a group contains a collection of zeroes and ones representing a binary code for a different symbol. Each group is followed by a single separator record containing
a single 9; the separator records are not part of the group. Each group is independent of other groups; the codes in one group are not related to codes in any other group (that is, each group is to be processed independently).
Output
For each group, your program should determine whether the codes in that group are immediately decodable, and should print a single output line giving the group number and stating whether the group is, or is not, immediately decodable.
Sample Input
01 10 0010 0000 9 01 10 010 0000 9
Sample Output
Set 1 is immediately decodable Set 2 is not immediately decodable
我的代码(数组字典树):
查找和插入放在主函数一次性完成了。
#include <bits/stdc++.h> using namespace std; struct node { int next[2]; int cnt; bool isWord; void init() { cnt=0; isWord=false; memset(next,-1,sizeof(next)); } }T[100000]; int main() { int kase=0,tot=1,flag=1; char s[100]; T[0].init(); while(~scanf("%s",s)) { int len=strlen(s); if(s[0]!='9') { int i,p=0; for(i=0;i<len;i++) { int x=s[i]-'0'; if(T[p].next[x]==-1) { T[tot].init(); T[p].next[x]=tot++; } p=T[p].next[x]; T[p].cnt++; if(T[p].isWord) flag=0; //包含其它串 } T[p].isWord=true; if(T[p].cnt>1) flag=0; //包含于其它串 }else{ printf("Set %d is%simmediately decodable\n",++kase,flag?" ":" not "); T[0].init(); tot=1,flag=1; } } return 0; }
指针字典树:
题目数据范围小胡搞:#include<stdio.h> #include<string.h> #include<stdlib.h> #include<iostream> using namespace std; const int MAXN = 2; typedef struct Trie_Node { bool isCode; struct Trie_Node *next[MAXN]; }Trie; bool flag; void Trie_insert(Trie *root,char *str) { Trie *p=root; int len=strlen(str); for(int i=0;i<len;i++) { int k=str[i]-'0'; if(p->next[k]==NULL) { Trie *t=new Trie; for(int j=0;j<MAXN;j++) t->next[j]=NULL; t->isCode=false; p->next[k]=t; } else { if(p->next[k]->isCode) { flag=false; return; } } p=p->next[k]; } p->isCode=true; } void Trie_del(Trie *root) { for(int i=0;i<MAXN;i++) { if(root->next[i]!=NULL) Trie_del(root->next[i]); } free(root); } char str[15]; int main() { int iCase=0; while(scanf("%s",str)!=EOF) { iCase++; Trie *root=new Trie; for(int i=0;i<MAXN;i++) root->next[i]=NULL; root->isCode=false; flag=true; Trie_insert(root,str); while(scanf("%s",str)) { if(str[0]=='9') break; if(flag) Trie_insert(root,str); } if(flag) printf("Set %d is immediately decodable\n",iCase); else printf("Set %d is not immediately decodable\n",iCase); Trie_del(root); } return 0; }
#include <cstdio> #include <cstring> #include <cmath> #include <iostream> #include <algorithm> #include <string> #include <cstdlib> using namespace std; int main() { char str[20][20],temp[20]; int ansNum=1,cnt=0,i,j,flag=1,len,t; while(~scanf("%s",temp)) { if(temp[0]=='9') { for(i=1;i<cnt;i++) { if(!flag) break; for(j=i+1;j<=cnt;j++) { if(!flag) break; len=min(strlen(str[i]),strlen(str[j])); for(t=0;t<len;t++) { if(str[i][t]!=str[j][t]) { flag=1; break; } flag=0; } } } if(flag) printf("Set %d is immediately decodable\n",ansNum); else printf("Set %d is not immediately decodable\n",ansNum); cnt=0,flag=1,ansNum++; memset(str,0,sizeof(str)); } else { strcpy(str[++cnt],temp); getchar(); } } }

本文介绍了一种算法,用于判断一组二进制编码是否为立即可解码的符号集,即任一编码都不是其他编码的前缀。通过两种不同的实现方式——数组字典树和指针字典树,来解决这一问题,并给出示例输入输出。
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