343. Integer Break
剪绳子的问题
DP方法:dp[n] = max( i*dp[n-i], i*(n - i) ) (其中i从1到n-1),时间复杂度O(n2)
class Solution(object):
def integerBreak(self, n):
"""
:type n: int
:rtype: int
"""
dp = [0] * (n + 1)
dp[1] = 1
dp[2] = 1
for i in range(3, n+1):
for j in range(1, i):
dp[i] = max(dp[i], dp[j]*(i-j), j*(i-j))
return dp[n]
贪心算法,把n尽可能的分成几个3相乘的形式,是有公式推导的,时间复杂度O(logn)
class Solution(object):
def integerBreak(self, n):
"""
:type n: int
:rtype: int
"""
if n == 2:
return 1
if n == 3:
return 2
if n % 3 == 0:
return pow(3, n/3)
if n % 3 == 1:
return 4 * pow(3, (n-4)/3)
else:
return 6 * pow(3, (n-5)/3)