A+B for Input-Output Practice

本文详细介绍了一款使用C++语言实现的简单求和程序,该程序能够接收一系列整数对作为输入,并输出每对整数的和。文章首先解释了程序的工作原理,然后提供了两种不同的实现方式,一种是使用标准输入输出流进行交互,另一种是预先定义输入次数并通过数组存储结果。此程序适用于C++初学者理解基本的输入输出操作及循环结构。

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//Problem Description
//Your task is to Calculate a + b.
//Too easy?! Of course! I specially designed the problem for acm beginners. 
//You must have found that some problems have the same titles with this one, yes, all these problems were designed for the same aim.

//Input
//The input will consist of a series of pairs of integers a and b, separated by a space, one pair of integers per line.

//Output
//For each pair of input integers a and b you should output the sum of a and b in one line, and with one line of output for each line in input.

//Sample Input
//1 5 
//10 20

//Sample Output 
//6 
//30

//Author
//小白 

//Creation time
//2018.12.04
#include<stdio.h>
int main(){
	int a,b;
	while(~scanf("%d%d",&a,&b))
		printf("%d\n",a+b);
	return 0;
}
//Problem Description
//Your task is to Calculate a + b.

//Input
//Input contains an integer N in the first line, and then N lines follow. Each line consists of a pair of integers a and b, separated by a space, one pair of integers per line.

//Output
//For each pair of input integers a and b you should output the sum of a and b in one line, and with one line of output for each line in input.

//Sample Input 
//2 
//1 5 
//10 20

//Sample Output 
//6 
//30

//Author
//小白 

//Creation time
//2018.12.04
#include<iostream>
#define M 1000
using namespace std;
int main(){
	int a,b,s[M],n;
	cin>>n;
	for(int i=0;i<n;i++){
		cin>>a>>b;
		s[i]=a+b;
	}
	for(int i=0;i<n;i++)
		cout<<s[i]<<endl;
	return 0;	
} 
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