Happy Number

LeetCode原题:Happy Number

Write an algorithm to determine if a number is "happy".

A happy number is a number defined by the following process: Starting with any positive integer, replace the number by the sum of the squares of its digits, and repeat the process until the number equals 1 (where it will stay), or it loops endlessly in a cycle which does not include 1. Those numbers for which this process ends in 1 are happy numbers.

Example: 19 is a happy number

12 + 92 = 82
82 + 22 = 68
62 + 82 = 100
12 + 02 + 02 = 1

主要内容:判断给定数是否符合条件


解题思想:除了会出现结果等于1的情况还会出现无限循环,要得出是否是无限循环从而得出否定的结论需要判断该循环是否属于有限循环(该类判断方法的循环类别)


参考C++代码:

class Solution {
public:
    int med(int n) {
        int b = 0;
        int c = 0;
        while(n != 0) {
            b = n % 10;
            c = c + b * b;
            n = n / 10;
        }
        return c;
    }
    bool isHappy(int n) {
        int b = n;
        set<int> s;
        while (med(b) != 1) {
            if (s.count(b)) {
                return false;
            } else {
                s.insert(b);
            }
            b =  med(b);
        }
        return true;
    }
};


评论
添加红包

请填写红包祝福语或标题

红包个数最小为10个

红包金额最低5元

当前余额3.43前往充值 >
需支付:10.00
成就一亿技术人!
领取后你会自动成为博主和红包主的粉丝 规则
hope_wisdom
发出的红包
实付
使用余额支付
点击重新获取
扫码支付
钱包余额 0

抵扣说明:

1.余额是钱包充值的虚拟货币,按照1:1的比例进行支付金额的抵扣。
2.余额无法直接购买下载,可以购买VIP、付费专栏及课程。

余额充值