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#include <iostream>#include<stdio.h>#include<string.h>#include<algorithm>using namespace std;const int N=4;int a[N]={3,3,3,5};float s=0;int main(){ if(N==2){ if(a[0]==a[1]){ cout << a[0]; //相同电池全部ok }else{ .

#include <iostream>#include<stdio.h>#include<string.h>#include<algorithm>using namespace std;const int N=6;const int H=40;int a[N]={6,18,11,13,19,11};int s=0;bool comp(int a,int b){ return a>b;}int main(){ //①从大-&.

#include <bits/stdc++.h>#include <cstdlib> #include <cstring> #include <string> #include <queue> using namespace std; int n[7]={0,0,0,4,0,0,1};//int n[7]={0,7,5,1,0,0,0};int total=0;int s;int yu=0;int main.

#include <bits/stdc++.h>#include <cstdlib> #include <cstring> #include <string> #include <queue> using namespace std; const int N=4;int a[N+1][N+1]={ //占位 {0,0,0,0,0}, {0,0,-2,-7,0}, {0,9,2,-6,2}, {0,-4,1.

#include <bits/stdc++.h>#include <cstdlib> #include <cstring> #include <string> #include <queue> using namespace std; int c=0;int len=0;char n[101];int main() { //流程图：分析 >> 敲码 -> ！不要用战术上的勤奋.