IN:
select
c.*,
sum(d.money) AS sumMoney,
REPLACE(GROUP_CONCAT(d.project_name), ',', '/') AS projectName
from test c
left join test_detail d ON c.id = d.fid
where 1=1
and c.id IN (
SELECT e.fid FROM test_detail e WHERE e.id = #{id}
)
EXISTS:
select
c.*,
sum(d.money) AS sumMoney,
REPLACE(GROUP_CONCAT(d.project_name), ',', '/') AS projectName
from test c
left join test_detail d ON c.id = d.fid
where 1=1
and EXISTS (
SELECT e.fid FROM test_detail e WHERE e.auditor_id = #{id} AND c.id = e.fid
)
not in 和not exists如果查询语句使用了not in 那么内外表都进行全表扫描,没有用到索引;而not extsts 的子查询依然能用到表上的索引。所以无论那个表大,用not exists都比not in要快。
in 与 =的区别
select name from student where name in ('zhang','wang','li','zhao');
与
select name from student where name='zhang' or name='li' or name='wang' or name='zhao'
的结果是相同的