在Service中弹出一个Dialog

最新推荐文章于 2025-06-13 14:12:01 发布

原创最新推荐文章于 2025-06-13 14:12:01 发布 · 1.5k 阅读

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#service #dialog

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本文介绍如何在Android Service中创建并显示一个具有自定义按钮和监听器的对话框。通过设置对话框类型为系统警告类型，确保其在前台正常显示。

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在Service中

public class MyService extends Service {

    private WindowManager windowManager;
    private WindowManager.LayoutParams params;
    private View view;
    private Button btn;
    private boolean isViewGroup;

    @Nullable
    @Override
    public IBinder onBind(Intent intent) {
        return null;
    }

    @Override
    public void onCreate() {

    }

    @Override
    public int onStartCommand(Intent intent, int flags, int startId) {
    AlertDialog.Builder builder = new AlertDialog.Builder(this);

    builder.setTitle("dialog")
        .setMessage("我是Dialog")
        .setNegativeButton("退出", new DialogInterface.OnClickListener() {
            @Override
            public void onClick(DialogInterface dialog, int which) {
                dialog.dismiss();
            }
        }).setOnKeyListener(new DialogInterface.OnKeyListener() {
            @Override
            public boolean onKey(DialogInterface dialog, int keyCode, KeyEvent event) {
                dialog.dismiss();
                return true;
            }
        });

    AlertDialog dialog = builder.create();
    dialog.getWindow().setType(WindowManager.LayoutParams.TYPE_SYSTEM_ALERT);
    dialog.show();

        return super.onStartCommand(intent, flags, startId);
    }


    @Override
    public void onDestroy() {
        super.onDestroy();
    }
}

权限：

<uses-permission android:name="android.permission.SYSTEM_ALERT_WINDOW"/>