打印从1到最大的n位数

输入数字n,按顺序打印从1到最大的n位十进制数。比如输入3,则打印1、2、3一直到最大的3位数999

class PrintMaxNumber {
public:
    PrintMaxNumber(int i = 1) :n(i) {}
    void Print1ToMaxOfN();
private:
    /*判断是否达到了最大的n位数*/
    bool Increment(char *number);
    void PrintNumber(char *number);
private:
    int n;
};
void PrintMaxNumber::Print1ToMaxOfN() {
    if (n <= 0) return;
    char *number = new char[n + 1];
    memset(number, '0', n);
    number[n] = '\0';
    while (!Increment(number)) {
        PrintNumber(number);
    }
    delete[]number;
}
bool PrintMaxNumber::Increment(char *number) {
    bool isOverflow = false;
    int nTakeOver = 0;
    int nLength = strlen(number);
    for (int i = nLength - 1; i >= 0; i--) {
        /*取出第i位的数值*/
        int nSum = number[i] - '0' + nTakeOver;
        /*如果i是个位，则加一*/
        if (i == nLength - 1)
            nSum++;
        /*如果nSum==10,说明第i位数字是9，加一后，需要进位操作*/
        if (nSum == 10) {
            /*i==0代表最高位*/
            if (0 == i)
                isOverflow = true;
            else {
                /*第i位置为0,进一*/
                nSum -= 10;
                nTakeOver = 1;
                number[i] = '0' + nSum;
            }
        }
        else {
            number[i] = '0' + nSum;
            break;
        }
    }
    return isOverflow;
}
void PrintMaxNumber::PrintNumber(char *number) {
    bool isBegin = true;
    int nLength = strlen(number);
    for (int i = 0; i < nLength; ++i) {
        if (isBegin && number[i] != '0') isBegin = false;
        if (!isBegin) cout << number[i];
    }
    cout << "\t";
}