低效的冒泡算法
list1 = [1,3,4,5,6,7,8,53,2]
# for i in range(100):
# list1.append(i)
count_num = 0
num = len(list1)
for i in range(num):
for j in range(num-1-i):
count_num += 1
if list1[j] < list1[j+1]:
temp = list1[j]
list1[j] = list1[j+1]
list1[j+1] = temp
print (list1,temp)
print (1,sorted(list1),count_num)