Codeforces Round #394 (Div. 2) A+B

本文解析了两道竞赛编程题目:一是通过判断偶数步和奇数步数量验证路径区间是否合理;二是通过比较两位运动员记录的障碍物距离,判断他们是否在同一赛道上。

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A. Dasha and Stairs

time limit per test:2 seconds

memory limit per test:256 megabytes

input:standard input

output:standard output

On her way to programming school tiger Dasha faced her first test — a huge staircase!

The steps were numbered from one to infinity. As we know, tigers are very fond of all striped things, it is possible that it has something to do with their color. So on some interval of her way she calculated two values — the number of steps with even and odd numbers.

You need to check whether there is an interval of steps from the l-th to the r-th (1 ≤ l ≤ r), for which values that Dasha has found are correct.

Input

In the only line you are given two integers a, b (0 ≤ a, b ≤ 100) — the number of even and odd steps, accordingly.

Output

In the only line print “YES”, if the interval of steps described above exists, and “NO” otherwise.

Examples

Input
2 3

Output
YES

Input
3 1

Output
NO

Note

In the first example one of suitable intervals is from 1 to 5. The interval contains two even steps — 2 and 4, and three odd: 1, 3 and 5.
题意:有a个偶数,b个奇数。问能否组成一个连续的序列(1<=l<=r)
题解:a,b的差的绝对值<=1即可。有一个cha点,当0 0时,是NO。
代码:

#include <bits/stdc++.h>
#define ll long long
using namespace std;
int main()
{
    int a,b;
    cin>>a>>b;
    if(a==0&&b==0) 
    {
        cout<<"NO"<<endl;
        return 0;
    }
    if(abs(a-b)<=1)
        cout<<"YES"<<endl;
    else
        cout<<"NO"<<endl;
}

B. Dasha and friends

time limit per test:2 seconds

memory limit per test:256 megabytes

input:standard input

output:standard output

Running with barriers on the circle track is very popular in the country where Dasha lives, so no wonder that on her way to classes she saw the following situation:

The track is the circle with length L, in distinct points of which there are n barriers. Athlete always run the track in counterclockwise direction if you look on him from above. All barriers are located at integer distance from each other along the track.

Her friends the parrot Kefa and the leopard Sasha participated in competitions and each of them ran one lap. Each of the friends started from some integral point on the track. Both friends wrote the distance from their start along the track to each of the n barriers. Thus, each of them wrote n integers in the ascending order, each of them was between 0 and L - 1, inclusively.

Consider an example. Let L = 8, blue points are barriers, and green points are Kefa’s start (A) and Sasha’s start (B). Then Kefa writes down the sequence [2, 4, 6], and Sasha writes down [1, 5, 7].
There are several tracks in the country, all of them have same length and same number of barriers, but the positions of the barriers can differ among different tracks. Now Dasha is interested if it is possible that Kefa and Sasha ran the same track or they participated on different tracks.

Write the program which will check that Kefa’s and Sasha’s tracks coincide (it means that one can be obtained from the other by changing the start position). Note that they always run the track in one direction — counterclockwise, if you look on a track from above.

Input

The first line contains two integers n and L (1 ≤ n ≤ 50, n ≤ L ≤ 100) — the number of barriers on a track and its length.

The second line contains n distinct integers in the ascending order — the distance from Kefa’s start to each barrier in the order of its appearance. All integers are in the range from 0 to L - 1 inclusively.

The second line contains n distinct integers in the ascending order — the distance from Sasha’s start to each barrier in the order of its overcoming. All integers are in the range from 0 to L - 1 inclusively.

Output

Print “YES” (without quotes), if Kefa and Sasha ran the coinciding tracks (it means that the position of all barriers coincides, if they start running from the same points on the track). Otherwise print “NO” (without quotes).

Examples

Input
3 8
2 4 6
1 5 7

Output
YES

Input
4 9
2 3 5 8
0 1 3 6

Output
YES

Input
2 4
1 3
1 2

Output
NO

Note

The first test is analyzed in the statement.
题意:操场上有多条长度为l的跑道,上面有n个障碍,两名选手以任意起始点开始逆时针跑,给出遇到每个障碍的距离。问两名选手是否可能在一条跑道。
题解:
我们不断调整一个人的起始点的位置,来和另一个人匹配。
代码:

#include <bits/stdc++.h>
#define ll long long
using namespace std;
int n,l,x;
int vis[200],a[200];
int main()
{
    cin>>n>>l;
    for(int i=0;i<n;i++)
    {
        cin>>x;
        vis[x]=1;
    }
    for(int i=0;i<n;i++) cin>>a[i];
    for(int i=0;i<l;i++)
    {
        bool flag=true;
        for(int j=0;j<n;j++)
        {
            if(!vis[(a[j]+i)%l])
                flag=false;
        }
        if(flag)
        {
        cout<<"YES"<<endl;
        return 0;
        }
    }
    cout<<"NO"<<endl;
}
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