Given an integer array of size n, find all elements that appear more than ⌊ n/3 ⌋ times.
Note: The algorithm should run in linear time and in O(1) space.
Example 1:
Input: [3,2,3]
Output: [3]
Example 2:
Input: [1,1,1,3,3,2,2,2]
Output: [1,2]
public class App
{
public static void main(String[] args){
int[] input = {3,2};
int num = input.length / 3;
System.out.println(num);
Arrays.sort(input);
System.out.println(Arrays.toString(input));
int m = input[0];
int n = 0;
for (int i=0; i<input.length; i++){
if (m != input[i]){
m = input[i];
n = i - n;
if (n > num){
System.out.println(input[i-1]);
}
}
if (i == input.length-1){
n = input.length -n;
if (n > num){
System.out.println(input[i]);
}
}
}
}
}