题目地址
https://leetcode-cn.com/problems/jump-game-ii/
题目描述
Given an array of non-negative integers nums, you are initially positioned at the first index of the array.
Each element in the array represents your maximum jump length at that position.
Your goal is to reach the last index in the minimum number of jumps.
You can assume that you can always reach the last index.
Example 1:
Input: nums = [2,3,1,1,4]
Output: 2
Explanation: The minimum number of jumps to reach the last index is 2.
Jump 1 step from index 0 to 1, then 3 steps to the last index.
Example 2:
Input: nums = [2,3,0,1,4]
Output: 2
Constraints:
- 1 <= nums.length <= 3 * 104
- 0 <= nums[i] <= 105
思路
贪心,找到从当前步跳到的步数加起来最远的位置,直到终点。
题解
class Solution {
public int jump(int[] nums) {
if(nums.length==1) return 0;
int max_pos = 0;
int next = 0;
int step=0;
for(int i=0;i<nums.length;){
step++;
if(i+nums[i]>= nums.length-1) return step;
max_pos = 0;
for(int j=0;j<=nums[i];++j){
if(j+nums[i+j]>max_pos){
max_pos = j+nums[i+j];
next = j;
}
}
i += next;
}
return step;
}
}
本文解析了如何使用贪心策略求解LeetCode题目Jump Game II,介绍了从当前位置出发的最大跳跃长度计算,以及如何找到达到终点的最少跳跃次数。通过实例演示和代码实现,帮助读者理解并掌握该算法。
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