c语言问题

char类型只有一个字节，汉字要占两个字节，故输入职工姓名时，应采用二维数组；

#include <stdio.h>
#include <string.h>
#define N 10
int main()
{
	void input(int[], char name[][8]); 
	void sort(int[], char name[][8]);
	void search(int, int[], char name[][8]);
	int num[N], number, flag = 1, c;
	char name[N][8];
	input(num, name);
	sort(num, name);
	while (flag == 1)
	{
		printf("\ninput number to look for:");
		scanf_s("%d", &number);
		search(number, num, name);
		printf("continue ot not(Y/N)?");
		getchar();
		c = getchar();
		if (c == 'N' || c == 'n')
			flag = 0;
	}
	return 0;
}
void input(int num[], char name[N][8]) //输入职工姓名和职工号
{
	int i;
	for (i = 0; i<N; i++)
	{
		printf("input NO.: ");
	   scanf_s("%d", &num[i]);  
	   printf("input name: ");
		getchar();  //scanf读入的是num[i]，按回车键后’\n‘还在缓冲区，getchar（）是为了清楚键盘缓冲区的回车符；
		            //否则，进行gets操作时，不等用户输入，直接输出“\n”；
		gets_s(name[i]);
	}
}
void sort(int num[], char name[N][8])//按职工号由大到小排序，姓名顺序随之调整；
{
	int i, j, min, templ;
	char temp2[8];
	for (i = 0; i<N - 1; i++)
	{
		min = i;
		for (j = i; j<N; j++)
			if (num[min]>num[j])  min = j;
		templ = num[i];
		strcpy_s(temp2, name[i]);
		num[i] = num[min];
		strcpy_s(name[i], name[min]);
		num[min] = templ;
		strcpy_s(name[min], temp2);
	}
	printf("\n result:\n");
	for (i = 0; i<N; i++)
		printf("\n %5d%10s", num[i], name[i]);
}
void search(int n, int num[], char name[N][8])//用折半法找出职工的姓名，从主函数输入要查找的职工号，输出该职工号。
{
	int top, bott, mid, loca, sign;
	top = 0;
	bott = N - 1;
	loca = 0;
	sign = 1;
	if ((n<num[0]) || (n>num[N - 1]))
		loca = -1;
	while ((sign == 1) && (top <= bott))
	{
		mid = (bott + top) / 2;
		if (n == num[mid])
		{
			loca = mid;
			printf("NO. %d , his name is %s.\n", n, name[loca]);
			sign = -1;
		}
		else if (n<num[mid])
			bott = mid - 1;
		else
			top = mid + 1;
	}
	if (sign == 1 || loca == -1)
		printf("%d not been found.\n", n);
}