/*
solution:
并查集
note:
注意每次调用getParent都要更新under数组。这是最容易出错的地方!
由于路径的压缩,所以每次更新under时都相当与沿着路径更新。
date:
2016.8.17
*/
#include <iostream>
#include <cstdio>
#include <cstring>
using namespace std;
const int maxn = 30000+5;
int parent[maxn], under[maxn], sum[maxn];
int n, p;
int getParent(int a) {
if(parent[a] == a) return a;
int t = getParent(parent[a]);
under[a] += under[parent[a]]; //note
parent[a] = t;
return parent[a];
}
void Merge(int a, int b) { //把a所在的堆放置到b所在的堆上面
int pa = getParent(a);
int pb = getParent(b);
if(pa == pb) return;
parent[pb] = pa;
under[pb] = sum[pa];
sum[pa] += sum[pb];
}
int main()
{
//freopen("input.txt", "r", stdin);
while(~scanf("%d", &p)) {
for(int i = 1; i <= 30000; i++) {
parent[i] = i;
under[i] = 0;
sum[i] = 1;
}
char op[5]; int obj1, obj2;
for(int i = 0; i < p; i++) {
scanf("%s", op);
if(op[0] == 'M') {
scanf("%d%d", &obj1, &obj2);
//printf("#%d %d\n", obj1, obj2);
Merge(obj2, obj1); //将obj1放在obj2上面
}
else {
scanf("%d", &obj2);
getParent(obj2);
printf("%d\n", under[obj2]);
}
}
}
return 0;
}
poj1988
最新推荐文章于 2023-12-01 20:40:29 发布