Python-列表转为字典的两个方法

1、现在有一个列表，list1 = [‘key1’,‘key2’,‘key3’]，把他转为这样的字典：{‘key1’:‘1’,‘key2’:‘2’,‘key3’:‘3’}

方法：再构造一个列表list2 = [‘1’,‘2’,‘3’]，使用zip转换为元组后，在将元组转换为字典

list1 = ['key1','key2','key3']
list2 = ['1','2','3']
dict(zip(list1,list2))
{'key1':'1','key2':'2','key3':'3'}

2、将嵌套列表转为字典，有两种方法，

new_list= [['key1','value1'],['key2','value2'],['key3','value3']]
dict(list)
{'key3': 'value3', 'key2': 'value2', 'key1': 'value1'}

或者这样：

new_list= [['key1','value1'],['key2','value2'],['key3','value3']]
new_dict = {}
 for i in new_list:
	new_dict[i[0]] = i[1]                #字典赋值，左边为key，右边为value
new_dict
{'key3': 'value3', 'key2': 'value2', 'key1': 'value1'}