一道w3c比较经典的小题目,开关灯泡。就是用js切换某个img的src地址~代码如下
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd">
<html xmlns="http://www.w3.org/1999/xhtml" xml:lang="en">
<head>
<meta http-equiv="Content-Type" content="text/html;charset=UTF-8">
<title>Document</title>
<script>
var checkCount = 0;
function checkStatus(){
var statusImg = document.getElementById('on');
if(statusImg.src.indexOf('on.gif') >= 0){
statusImg.src = './images/off.gif';
}else{
statusImg.src = './images/on.gif';
}
console.log('点击次数为:'+checkCount++);
}
</script>
</head>
<body>
<img src="./images/off.gif" alt="" onclick="checkStatus();" id = "on"/>
</body>
</html>