C.Primer.Plus(第六版)第五章编程练习

C.Primer.Plus(第六版)第五章编程练习 windows+vc 6.0

#include<iostream>
#include<string>
using namespace std;

int main()
{   
/*  //5.1 计算并输出两个之间所有数的和。
    int num1,num2,sum=0;
    cout<<"Please input two intergr number:";
    cin>>num1>>num2;//假设先输入小的数
    if(num1>num2)
    {
        int temp=num1;
        num1=num2;
        num2=temp;
    }
    for(;num1<=num2;num1++)
    {
        sum+=num1;  
    }
    cout<<"the sum number is "<<sum<<endl;
*/
    //5.2 编译器不支持array模板类，未测试。
/*
    //5.3 计算输入的所有数字的和并实时输出，检测到0结束
    int sum=0,int_enter;
    cout<<"Please enter a interger number:";
    cin>>int_enter;

    while(int_enter!=0)
    {
        sum+=int_enter;
        cout<<"the sum number is "<<sum<<endl;
        cout<<"Please enter a interger number:";//提示再次输入
        cin>>int_enter;//不能忽略，否则死循环。
    }
    cout<<"END，the total sum number is "<<sum<<endl;
*/
/*  //5.4计算二者的投资情况
    float daphne=100,cleo=100,benjin=100;
    const float danli=0.1f;//忘记将int更改类型为float，结果一直死循环。（二者一直为100）
    const float fuli=0.05f;
    int year=0;
    while(daphne>=cleo)
    {
        daphne+=danli*benjin;
        cleo+=fuli*cleo;
        year++;
    }
    cout<<year<<" years,cleo money more than daphne and cleo money is "<<cleo<<" daphne money is "<<daphne<<endl;
*/
/*  //5.5 记录销售量
    char* month[12]={"one","two","three","four","five","six","seven","eight","nine","ten","eleven","twelve"};//类型为char* ，存储的是字符串常量的地址。
//  string month={"one","two","three","four","five","six","seven","eight","nine","ten","eleven","twelve"};
    int number[12]={0},sum=0;
    for(int i=0;i<12;i++)
    {
        cout<<"Please enter the "<<month[i]<<" month number :";
        cin>>number[i];
        sum+=number[i];
    }
    cout<<"The all year number is "<<sum<<endl;
*/
/*  //5.6 记录3年的销售量                                                                                                       
    char* month[12]={"one","two","three","four","five","six","seven","eight","nine","ten","eleven","twelve"};//类型为char* ，存储的是字符串常量的地址。
//  string month={"one","two","three","four","five","six","seven","eight","nine","ten","eleven","twelve"};
    int number[3][12]={0},sum[3]={0};
    for(int j=0;j<3;j++)
    {
        for(int i=0;i<12;i++)
        {
            cout<<"Please enter the "<<j+1<<" year "<<month[i]<<" month number :";
            cin>>number[j][i];
            sum[j]+=number[j][i];
        }
        cout<<"the "<<j+1<<" year number is "<<sum[j]<<endl;
    }
    cout<<"and the all year number is "<<sum[0]+sum[1]+sum[2]<<endl;    
*/  
/*  //第五章5.7
    struct car
    {
        char name[20];
        int year;
    };
    cout<<"How many cars do you wish to catalog:";
    int car_number;
    cin>>car_number;
    cin.get();
    car* array = new car[car_number];//
    for(int i=0;i<car_number;i++)
    {   
        cout<<"Car #"<<i+1<<endl;
        cout<<"Please enter the make:";
        cin.getline((*(array+i)).name,20);
        cout<<"Please enter the year made:";
        cin>>(*(array+i)).year;
        cin.get();//如果不消除的话，下次循环会检测到上面这个换行符。
    }
    cout<<"Here is your collection:"<<endl;
    for(int j=0;j<car_number;j++)
    {
        cout<<(*(array+j)).year<<'\t'<<(*(array+j)).name<<endl;
    }
    delete array;//非常重要
*/
/*  //5.8 读取单词，done为结束条件。
    cout<<"Enter word(to stop,enter the word done):";
    char name[20];
    int count=0;
    cin>>name;
    while(strcmp(name,"done"))
    {
        cin>>name;
        count++;
    }
    cout<<"You entered a total of "<<count<<" words"<<endl;
*/  
/*  //5.9 使用string对象实现5.8
    cout<<"Enter word(to stop,enter the word done):";
    string name;
    int count=0;
    cin>>name;
    while(name!="done")
    {
        cin>>name;
        count++;
    }
    cout<<"You entered a total of "<<count<<" words"<<endl;

*/
/*  //5.10 嵌套循环输出图形
    int number=0;
    const int yihangyuansu=6;//一行元素的个数。
    cout<<"Enter number of rows:";
    cin>>number;
    for(int i=0;i<number;i++)
    {
        for(int j=i+1;j<yihangyuansu;j++)
        {
            cout<<"."<<'\t';
        }
        for(int k=0;k<=i;k++)
        {
            cout<<"*"<<'\t';
        }
        cout<<endl;
    }
*/
    return 0;
}