Accepted丶

水题一道，用二分解决问题 但由于涉及浮点数，可能引起精度误差，注意一下就好。//#include <bits/stdc++.h>//#define _ ios_base::sync_with_stdio(0);cin.tie(0);#include <iostream>#include <sstream>#include <iomanip>#include <vector>#inclu

#include <bits/stdc++.h>#define _ ios_base::sync_with_stdio(0);cin.tie(0);#include <iostream>#include <sstream>#include <iomanip>#include <vector>#include <deque>#include <list>#include <set>#i

#include <bits/stdc++.h>#define _ ios_base::sync_with_stdio(0);cin.tie(0);#include <iostream>#include <sstream>#include <iomanip>#include <vector>#include <deque>#include <list>#include <set>#i

//#include <bits/stdc++.h>//define _ ios_base::sync_with_stdio(0);cin.tie(0);#include <iostream>#include <sstream>#include <iomanip>#include <vector>#include <deque>#include <list>#include <set>

Problem A ZOJ 1004 Anagrams by Stack 题意：给你两个串，一个原串，一个目标串，让你借用栈来得出所有的使原串变成目标串的序列。 解法：借用DFS递归求解，先进栈，后出栈，当出入栈次数刚好为原单词的长度时，目标单词构造完毕，输出操作序列#include <bits/stdc++.h>#define INF 0x3f3f3f3f#define eps 1