PS:
附上CDOJ最短路的另外一发代码:
http://www.acm.uestc.edu.cn/#/problem/show/30
#include <iostream>
#include <sstream>
#include <iomanip>
#include <vector>
#include <deque>
#include <list>
#include <set>
#include <map>
#include <stack>
#include <queue>
#include <bitset>
#include <string>
#include <numeric>
#include <algorithm>
#include <functional>
#include <iterator>
#include <cstdio>
#include <cstring>
#include <cmath>
#include <cstdlib>
#include <cctype>
#include <complex>
#include <ctime>
#define INF 0x3f3f3f3f
#define eps 1e-6
typedef long long LL;
const double pi = acos(-1.0);
const long long mod = 1e9 + 7;
using namespace std;
int a[105][105];
int dis[105];
bool vis[105];
int main()
{
//freopen("int.txt","r",stdin);
//freopen("out.txt","w",stdout);
int N,M;
while(scanf("%d %d",&N,&M) != EOF)
{
if(N == 0 && M == 0)
break;
for(int i = 1;i <= N;i++)
for(int j = 1;j <= N;j++)
a[i][j] = INF;
int A,B,C;
for(int i = 1;i <= M;i++)
{
scanf("%d %d %d",&A,&B,&C);
a[A][B] = a[B][A] = C;
}
memset(vis,0,sizeof(vis));
for(int i = 1;i <= N;i++)
dis[i] = INF;
dis[1] = 0;
for(int i = 1;i <= N;i++)
{
int minp = -1;
int mind = INF;
for(int j = 1;j <= N;j++)
{
if(!vis[j] && dis[j] < mind)
{
mind = dis[j];
minp = j;
}
}
if(minp == -1 || minp == N)
break;
vis[minp] = 1;
for(int j = 1;j <= N;j++)
{
if(!vis[j])
dis[j] = min(mind + a[minp][j] , dis[j]);
}
}
if(dis[N] >= INF)
puts("Impossible");
else
printf("%d\n",dis[N]);
}
return 0;
}