SpringMVC实现简单登陆功能

最新推荐文章于 2022-10-21 19:31:50 发布

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最新推荐文章于 2022-10-21 19:31:50 发布

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分类专栏： JAVA 文章标签： spring mvc

本文链接：https://blog.youkuaiyun.com/qq_28174471/article/details/52488873

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本文详细介绍了如何使用SpringMVC实现一个简单的登录功能，包括添加依赖、配置自动扫描、视图解析、web.xml配置、创建登录页面、Controller代码编写以及Tomcat服务器配置。通过步骤化的指导，读者可以理解并实现一个基本的SpringMVC登录系统。

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SpringMVC实现简单的登陆

1. 在pom.xml中加入相应的依赖

<properties>

<org.springframework.version>3.2.4.RELEASE</org.springframework.version>

</ properties>

<dependency>
    <groupId>org.springframework</groupId>
    <artifactId>spring-aop</artifactId>
    <version>${org.springframework.version}</version>
</dependency>

<dependency>
    <groupId>org.springframework</groupId>
    <artifactId>spring-beans</artifactId>
    <version>${org.springframework.version}</version>
</dependency>

<dependency>
    <groupId>org.springframework</groupId>
    <artifactId>spring-context</artifactId>
    <version>${org.springframework.version}</version>
</dependency>
<dependency>

<dependency>
    <groupId>org.springframework</groupId>
    <artifactId>spring-core</artifactId>
    <version>${org.springframework.version}</version>
</dependency>
<dependency>
    <groupId>org.springframework</groupId>
    <artifactId>spring-expression</artifactId>
    <version>${org.springframework.version}</version>
</dependency>

<dependency>
    <groupId>org.springframework</groupId>
    <artifactId>spring-webmvc</artifactId>
    <version>${org.springframework.version}</version>
</dependency>

<dependency>
    <groupId>org.springframework</groupId>
    <artifactId>spring-web</artifactId>
    <version>${org.springframework.version}</version>
</dependency>

<dependency>
    <groupId>commons-logging</groupId>
    <artifactId>commons-logging</artifactId>
    <version>1.1.2</version>
</dependency>

2. 建包，建类

3. springMVC配置文件

配置自动扫描

<context:component-scan base-package="com.neusoft.spring.springMVC">
<context:include-filtertype="annotation" expression="org.springframework.stereotype.Controller"/>
</context:component-scan>

设置视图解释

4. web.xml配置

<servlet>
    <servlet-name>dispatcher</servlet-name>
    <servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
    <init-param>
        <param-name>contextConfigLocation</param-name>
        <param-value>classpath:spring-mvc.xml</param-value>
    </init-param>
</servlet>
<servlet-mapping>
    <servlet-name>dispatcher</servlet-name>
    <url-pattern>/</url-pattern>
</servlet-mapping>

5. 建立登陆页面

登陆主界面

<%@page contentType="text/html;charset=UTF-8" language="java" isELIgnored="false" %>
<html>
<head>
    <title></title>
</head>
<body>
<h1>登陆界面</h1>
<form action="loginin"method="post">
    <table>
      <tr>
        <td>姓名：</td><td><inputtype="text" name="userName"> </td>
      </tr>
      <tr>
        <td>密码：</td><td><inputtype="text" name="passWord"> </td>
      </tr>
      <tr>
        <td><input type="submit" value="提交"> </td>
      </tr>
    </table>
    <font color="red">${error}</font>
</form>

登陆成功界面

6. Controller类里面实现

1. 转入登陆主界面

@RequestMapping("tologin")
public ModelAndView toLoginView(){
return new ModelAndView("login");
}

2. 点击按钮后判断

@RequestMapping(value = "loginin",method= RequestMethod.POST)
public ModelAndView loginEvent(@RequestParam(value= "userName") String userName,@RequestParam(value = "passWord") String password){
  ModelAndView sucees = new ModelAndView("loginsuccess");

    String uname = userName;
    String upassWprd = password;
    if(uname == null|| "".equals(uname)){
        return new ModelAndView("login","error","用户名不能为空");
    }
    if(upassWprd== null || "".equals(upassWprd)){
        return new ModelAndView("login","error","密码不能为空");
    }
    if(!uname.equals("admin") && !upassWprd.equals("123")){
        return new ModelAndView("login","error","用户名或密码输入错误");
    }
    return new ModelAndView("loginsuccess");
}

7. 配置tomcat

8. 运行