C语言习题：排序+打印3的倍数+打印公约数+打印闰年-优快云博客

本文链接：https://blog.youkuaiyun.com/qq_27928443/article/details/127854554

本文展示了四个C语言程序，分别用于实现数组元素排序、打印3的倍数、计算两个数的最大公约数以及找出1000年至2000年间的所有闰年。程序通过条件判断和循环操作，实现了基本的算法功能，适合初学者学习和理解C语言基础操作。

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1.排序

int main()
{
   int a = 0;
   int b = 0;
   int c = 0;
   scanf("%d%d%d", &a, &b, &c);
   if (a < b)
   {
       int tep = a;
       a = b;
       b = tep;
   }
   if (a < c)
   {
       int tep = a;
       a = c;
       c = tep;
   }
   if (b<c)
   {
       int tep = b;
       b = c;
       c = tep;
   }
   printf("%d %d %d\n", a, b, c);
   return 0;
}

int main()
{
	int a = 0;
	int b = 0;
	int c = 0;
	scanf("%d%d%d", &a, &b, &c);
	if (a < b)
	{
		int tep = a;
		a = b;
		b = tep; 
	}
	if (a < c)
	{
		int tep = a;
		a = c;
		c = tep;
	}
	if (b<c)
	{
		int tep = b;
		b = c;
		c = tep;
	}
	printf("%d %d %d\n", a, b, c);
	return 0;
}

2.打印3的倍数

int main()
{
   int i = 0;
   for (i = 1; i <= 100; i++)
   {
       if (i % 3 == 0)
           printf("%d ", i);
   }

return 0;
}

int main()
{
	int i = 0;
	for (i = 1; i <= 100; i++)
	{
		if (i % 3 == 0)
			printf("%d ", i);
	}

	return 0;
}

3.打印公约数

int main()
{
   int m = 0;
   int n = 0;
   scanf("%d%d", &m, &n);
   if (m < n)
   {
       int tep = m;
       m = n;
       n = tep;
   }
   while (m % n)
   {
       int r = m % n;
       m = n;
       n = r;
   }
   printf("%d\n", n);
   return 0;
}

int main()
{
	int m = 0;
	int n = 0;
	scanf("%d%d", &m, &n);
	if (m < n)
	{
		int tep = m;
		m = n;
		n = tep;
	}
	while (m % n)
	{
		int r = m % n;
		m = n;
		n = r;
	}
	printf("%d\n", n);
	return 0;
}

4.打印闰年

int main()
{
   int year = 0;
   for (year = 1000; year <= 2000; year++)
   {
       //判断year是否为闰年：1.能被4整除切不能被100整除是闰年；2.能被400整除是闰年
       if (year % 4 == 0 && year % 100 != 0)
       {
           printf("%d ", year);
       }
       else if (year % 400 == 0)
       {
           printf("%d ", year);
       }
   }
   return 0;
}

int main()
{
	int year = 0;
	for (year = 1000; year <= 2000; year++)
	{
		//判断year是否为闰年：1.能被4整除切不能被100整除是闰年；2.能被400整除是闰年
		if (year % 4 == 0 && year % 100 != 0)
		{
			printf("%d ", year);
		}
		else if (year % 400 == 0)
		{
			printf("%d ", year);
		}
	}
	return 0;
}