/**
* Definition for a binary tree node.
* public class TreeNode {
* int val;
* TreeNode left;
* TreeNode right;
* TreeNode() {}
* TreeNode(int val) { this.val = val; }
* TreeNode(int val, TreeNode left, TreeNode right) {
* this.val = val;
* this.left = left;
* this.right = right;
* }
* }
*/
class Solution {
public List<Integer> inorderTraversal(TreeNode root) {
List<Integer> ls = new ArrayList();
if(root==null)
return ls;
Deque<TreeNode> deque = new LinkedList();
deque.push(root);
while(!deque.isEmpty()){
TreeNode node = deque.pop();
if(node!=null){
// 前序
// if(node.right!=null)
// deque.push(node.right);
// if(node.left!=null)
// deque.push(node.left);
// deque.push(node);
// deque.push(null);
//中序
// if(node.right!=null)
// deque.push(node.right);
// deque.push(node);
// deque.push(null);
// if(node.left!=null)
// deque.push(node.left);
//后序
deque.push(node);
deque.push(null);
if(node.right!=null)
deque.push(node.right);
if(node.left!=null)
deque.push(node.left);
}else{
node = deque.pop();
ls.add(node.val);
}
}
return ls;
}
}
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