class NumArray {
public:
void build_segment_tree(vector<int>& value, vector<int>& nums, int pos, int left, int right)
{
if(left == right)
{
value[pos] = nums[left];
return;
}
int mid = (left + right) / 2;
build_segment_tree(value, nums, pos * 2 + 1, left, mid);
build_segment_tree(value, nums, pos * 2 + 2, mid + 1, right);
value[pos] = value[pos * 2 + 1] + value[pos * 2 + 2];
}
//线段树求和
int sum_range_segment_tree(vector<int>& value, int pos, int left, int right, int qleft, int qright)
{
if(right < qleft || left > qright)
return 0;
if(right <= qright && left >= qleft)
return value[pos];
int mid = (left + right) / 2;
return sum_range_segment_tree(value, pos * 2 + 1, left, mid, qleft, qright) + sum_range_segment_tree(value, pos * 2 + 2, mid + 1, right, qleft, qright);
}
//线段树更新
void update_segment_tree(vector<int>& value, int pos, int left, int right, int index, int new_value)
{
if(left == right && left == index)
{
value[pos] = new_value;
return;
}
int mid = (left + right) / 2;
if(index <= mid)
update_segment_tree(value, pos * 2 + 1, left, mid, index, new_value);
else
update_segment_tree(value, pos * 2 + 2, mid+1, right, index, new_value);
value[pos] = value[pos * 2 + 1] + value[pos * 2 + 2];
}
NumArray(vector<int> nums) {
if(nums.size() == 0)
return;
int n = nums.size() *4;//一般线段树数组大小是原数组大小的4倍
for(int i =0;i<n;++i)
value.push_back(0);
build_segment_tree(value,nums,0,0,nums.size()-1);
right_end = nums.size() -1 ;//线段的右端点
}
void update(int i, int val) {
update_segment_tree(value,0,0,right_end,i,val);
}
int sumRange(int i, int j) {
return sum_range_segment_tree(value,0,0,right_end,i,j);
}
private:
vector<int> value;
int right_end;
};
/**
* Your NumArray object will be instantiated and called as such:
* NumArray obj = new NumArray(nums);
* obj.update(i,val);
* int param_2 = obj.sumRange(i,j);
*/
区域和检索 - 数组可修改
最新推荐文章于 2025-04-21 09:28:21 发布