es聚合

最新推荐文章于 2025-02-15 21:19:44 发布

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最新推荐文章于 2025-02-15 21:19:44 发布

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分类专栏： elasticSearch ELK

本文链接：https://blog.youkuaiyun.com/qq_22041375/article/details/103690395

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本文详细介绍如何使用Elasticsearch的Java API进行复杂的数据聚合查询，包括计算球队球员数量、球员年龄统计、球队薪资总额及平均年龄等。通过对比SQL查询语句，深入解析ES的Terms、Max、Min、Sum、Avg等聚合函数的使用方法。

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https://www.cnblogs.com/xionggeclub/p/7975982.html

如要计算每个球队的球员数，如果使用SQL语句，应表达如下：

select team, count(*) as player_count from player group by team;
ES的java api：

TermsBuilder teamAgg= AggregationBuilders.terms("player_count ").field("team");
sbuilder.addAggregation(teamAgg);
SearchResponse response = sbuilder.execute().actionGet();

group by多个field
例如要计算每个球队每个位置的球员数，如果使用SQL语句，应表达如下：

select team, position, count(*) as pos_count from player group by team, position;
ES的java api：

TermsBuilder teamAgg= AggregationBuilders.terms("player_count ").field("team");
TermsBuilder posAgg= AggregationBuilders.terms("pos_count").field("position");
sbuilder.addAggregation(teamAgg.subAggregation(posAgg));
SearchResponse response = sbuilder.execute().actionGet();

max/min/sum/avg
例如要计算每个球队年龄最大/最小/总/平均的球员年龄，如果使用SQL语句，应表达如下：

select team, max(age) as max_age from player group by team;
ES的java api：

TermsBuilder teamAgg= AggregationBuilders.terms("player_count ").field("team");
MaxBuilder ageAgg= AggregationBuilders.max("max_age").field("age");
sbuilder.addAggregation(teamAgg.subAggregation(ageAgg));
SearchResponse response = sbuilder.execute().actionGet();

对多个field求max/min/sum/avg
例如要计算每个球队球员的平均年龄，同时又要计算总年薪，如果使用SQL语句，应表达如下：

select team, avg(age)as avg_age, sum(salary) as total_salary from player group by team;
ES的java api：

TermsBuilder teamAgg= AggregationBuilders.terms("team");
AvgBuilder ageAgg= AggregationBuilders.avg("avg_age").field("age");
SumBuilder salaryAgg= AggregationBuilders.avg("total_salary ").field("salary");
sbuilder.addAggregation(teamAgg.subAggregation(ageAgg).subAggregation(salaryAgg));
SearchResponse response = sbuilder.execute().actionGet();

聚合后对Aggregation结果排序
例如要计算每个球队总年薪，并按照总年薪倒序排列，如果使用SQL语句，应表达如下：

select team, sum(salary) as total_salary from player group by team order by total_salary desc;
ES的java api：

TermsBuilder teamAgg= AggregationBuilders.terms("team").order(Order.aggregation("total_salary ", false);
SumBuilder salaryAgg= AggregationBuilders.avg("total_salary ").field("salary");
sbuilder.addAggregation(teamAgg.subAggregation(salaryAgg));
SearchResponse response = sbuilder.execute().actionGet();

需要特别注意的是，排序是在TermAggregation处执行的，Order.aggregation函数的第一个参数是aggregation的名字，第二个参数是boolean型，true表示正序，false表示倒序。 

Aggregation结果条数的问题
默认情况下，search执行后，仅返回10条聚合结果，如果想反悔更多的结果，需要在构建TermsBuilder 时指定size：

TermsBuilder teamAgg= AggregationBuilders.terms("team").size(15);
 

Aggregation结果的解析/输出
得到response后：

Map<String, Aggregation> aggMap = response.getAggregations().asMap();
StringTerms teamAgg= (StringTerms) aggMap.get("keywordAgg");
Iterator<Bucket> teamBucketIt = teamAgg.getBuckets().iterator();
while (teamBucketIt .hasNext()) {
Bucket buck = teamBucketIt .next();
//球队名
String team = buck.getKey();
//记录数
long count = buck.getDocCount();
//得到所有子聚合
Map subaggmap = buck.getAggregations().asMap();
//avg值获取方法
double avg_age= ((InternalAvg) subaggmap.get("avg_age")).getValue();
//sum值获取方法
double total_salary = ((InternalSum) subaggmap.get("total_salary")).getValue();
//...
//max/min以此类推
}