//Map转换成JSON Map<String,String> map = new HashMap<String,String>(); map.put("a","aaa"); map.put("b","bbb"); map.put("c","ccc"); String json=JSON.toJSONString(map); System.out.println(json);//输出{"a":"aaa","b":"bbb","c":"ccc"} /*注意:toJSONString这个方法,如果map中的value有list,而list有对象,则此对象的String字段的变量头一个字母会默认为小写, 如 private String XMLB;会变成xMLB;(为什么?求解决)*/
//JSON转换成Map Map map1 = JSON.parseObject(json); System.out.println(map1.get("a")); for (Object mapData : map.entrySet()) { Map.Entry<String,String> entry = (Map.Entry<String,String>)mapData; System.out.println(entry.getKey()+"--->"+entry.getValue()); } /*输出 b--->bbb c--->ccc a--->aaa */ map中含有对象Map -> JSON //Map -> JSON Map<String,Bar> map = new HashMap<String, Bar>(); map.put("a",new Bar()); map.put("b",new Bar()); map.put("c",new Bar()); String json = JSON.toJSONString(map,true); System.out.println(json); /* 输出{ "a":{ "barAge":383687382, "barDate":1494945882018, "barName":"name_1689176802" }, "b":{ "barAge":-100528778, "barDate":1494945882018, "barName":"name_-878176366" }, "c":{ "barAge":-344075192, "barDate":1494945882018, "barName":"name_-1710740534" } } */ //JSON -> Map Map<String,Bar> map1 = (Map<String,Bar>)JSON.parse(json); for (String key : map1.keySet()) { System.out.println(key+":"+map1.get(key)); } /*输出 b:{"barAge":-100528778,"barDate":1494945882018,"barName":"name_-878176366"} c:{"barAge":-344075192,"barDate":1494945882018,"barName":"name_-1710740534"} a:{"barAge":383687382,"barDate":1494945882018,"barName":"name_1689176802"} */
json和map的转换
最新推荐文章于 2023-08-10 11:00:53 发布