Java字符脱敏逻辑

最新推荐文章于 2025-06-06 10:45:39 发布

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字符脱敏算法，简单脱俗的脱敏逻辑

String Name = MapName.get("Name") == null ? "" : MapName.get("Name").toString();
if (Name.length() < 1) {
		Name = "****";
} else if (Name.length() == 1) {
		Name = "****" + Name;
} else if (Name.length() == 2) {
		Name = Name.substring(1);
		Name = "****" + Name;
} else if (Name.length() == 3) {
		Name = Name.substring(2);
		Name = "****" + Name;
} else if(Name.length() > 3 && Name.length() < 7) {
		Name = consName.substring(0,2) + "****" + Name.substring(3);
}else{
		Name = Name.substring(0,2) + "****" + Name.substring(Name.length()-4);
}
		MapName.put("Name",Name);

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