2021-4-5知识点(正则表达式探测嵌套括号的深度)

正则表达式探测嵌套括号的深度

	let mStr = "(1+(2*3)+((8)/4))+1";
	let mCount = 0;
	while(mStr.indexOf("(")!==-1){
		mCount++;
		mStr = mStr.replace(/\([^\(\)]*\)/g,'');
	}
	console.log(mCount);