hdu-A == B ?

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A == B ?

Time Limit: 1000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)
Total Submission(s): 62097    Accepted Submission(s): 9737

Problem Description

Give you two numbers A and B, if A is equal to B, you should print "YES", or print "NO".

 

Input

each test case contains two numbers A and B.

 

Output

for each case, if A is equal to B, you should print "YES", or print "NO".

 

Sample Input

  

   1 2
2 2
3 3
4 3
  

 

Sample Output

  

   NO
YES
YES
NO
  

 

代码:

#include<stdio.h>
#include<string.h>
char a[100000],b[100000];//数组要适当开大点,否则会过不了
bool f(char a[],int len) //判断输入的数据是否含有小数点
{
	int i;
	for(i=0;i<len;++i)
	if(a[i]=='.')
		return true;
	return false;
}
void g(char a[],int len1)  //功能:若数据含有小数点,去除末尾的无效0,若不含小数点,在末尾补加以为"."
{
	if(f(a,len1))
		{
		  for(int k=len1-1;k>=0;--k)
		  {
		  	if(a[k]!='0')
		  	break;
		  	else
		  	a[k]='\0';
		  }
		}
		else
		{
			a[len1]='.';
		}
}
int main() 
{
	
	
	while(~scanf("%s%s",a,b))
	{
		int i,j,len1=strlen(a),len2=strlen(b);
		for(i=0;;++i)
		if(a[i]!='0')
		break;
		for(j=0;j>0;++j)
		if(b[j]!='0')
		break;
		g(a,len1);
		g(b,len2);
		if(strcmp(a+i,b+j)==0)
		printf("YES\n");
		else
		printf("NO\n");
		memset(a,0,sizeof(a));
		memset(b,0,sizeof(b));
	}
	return 0;
}