在假期利用Python完成了《数值分析》第二章的计算实习题,主要实现了牛顿插值法和三次样条插值,给出了自己的实现与调用Python包的实现——现在能搜到的基本上都是MATLAB版,或者是各种零碎的版本。
代码如下:
(第一题使用的自己的程序,第二第三题使用的Python自带库)
import math
import matplotlib.pyplot as plt
import numpy as np
import pandas as pd
from numpy.linalg import solve
from scipy import interpolate
from scipy.interpolate import lagrange
plt.rc('figure',figsize=(20,15))
print("Problem I:")
given_x=[0.2,0.4,0.6,0.8,1.0]
given_y=[0.98,0.92,0.81,0.64,0.38]
given_times=4
x_range=(0,1.1,0.02)
#@brief: Convert(begin,end,interval) to a list, but interval can be float numbers.
def process_xpara(xpara):
max_times=0
if 0<xpara[2]<1:
tmp_xpara_interval=xpara[2]
while tmp_xpara_interval-int(tmp_xpara_interval)!=0:
max_times=max_times+1
tmp_xpara_interval=tmp_xpara_interval*10
max_times=10**max_times
return [i/max_times for i in range(int(xpara[0]*max_times),int(xpara[1]*max_times),int(xpara[2]*max_times))]
def divide_difference(x,y,times):
now=[(x[i],y[i])