这题属于 shortest path problem的一种,我并没有用 dijkstra 而是 floyd 求解。
时间复杂度略逊 O(|V|3)
#include <cstdio>
#include <cmath>
#include <algorithm>
using namespace std;
struct coordinate_type{
int x;
int y;
};
coordinate_type pos[1001];
double Dis[1001][1001];
int main()
{
int N, Case = 1;
while (scanf("%d", &N) && N) {
for (int i = 1; i <= N; ++i)
scanf("%d %d", &pos[i].x, &pos[i].y);
for (int i = 1; i <= N; ++i)
for (int j = i + 1; j <= N; ++j)
Dis[i][j] = Dis[j][i] = sqrt(pow(pos[i].x - pos[j].x, 2) + pow(pos[i].y - pos[j].y, 2));
for (int k = 1; k <= N; ++k)
for (int i = 1; i <= N; ++i)
for (int j = 1; j <= N; ++j)
Dis[i][j] = min(Dis[i][j], max(Dis[i][k], Dis[k][j]));
printf("Scenario #%d\n", Case++);
printf("Frog Distance = %.3f\n\n", Dis[1][2]);
}
}