//1.编写实现strlen同功能的函数stringLength
int stringLength(char arr[]){
int i = 0;
while (arr[i] != '\0') {
i++;
}
return i;
}
//2.编写实现strcpy同功能的函数stringCopy
char * stringCopy(char arr1[],char arr2[]){
int totalA = stringLength(arr1);
int totalB = stringLength(arr2);
for (int i = 0; i < totalB; i++) {
arr1[i] = arr2[i];
}
for (int i = totalB; i < totalA; i++) {
arr1[i] = '\0';
}
return arr1;
}
//3.编写实现strcat同功能的函数stringCatch
char * stringCatch(char arr1[],char arr2[]){
int totalA = stringLength(arr1) + stringLength(arr2);
int totalB = stringLength(arr1);
int j = 0;
for (int k = totalB; k < totalA; k++) { //若k = stringLength(arr1) + stringLength(arr2)(赋表达式),k经每个循环都会变化
arr1[k] = arr2[j];
j++;
}
return arr1;
}
//笔记:
void stringCatchN(char arr1[],char arr2[]){
int length = stringLength(arr1);
int i = 0;
while (arr2[i] != '\0') {
arr1[length + i] = arr2[i];
}
}
//4.编写实现strcmp同功能的函数stringCompare
int stringCompareN(char arr1[],char arr2[]){
int i = 0;
while (arr1[i] == arr2[i]) {
i++;
}
//跳出循环的时候,说明两个字符数组的下标为i的字符是不一样的
int result = arr1[i] - arr2[i];//计算ASCII码的差值
return result;
}
C - 函数 Homework
最新推荐文章于 2025-03-10 20:49:12 发布