ajax success中无法return和无法赋值,是因为异步的问题,将async设为true解决
$.ajax({
url: "../aaaaaaaa/aaaaaaaaa.ht",
type: "post",
datatype: "json",
data: {"name": name, "type": type},
async: true,
success: function (data) {
return json[0].zrsx.toString();
}
}
})