//主要感悟:
//建哈夫曼树使用优先队列能够显著减少代码量,也比较容易实现。
//建立一个哈希表,每个字符与一个数字对应,这样编程比较方便
#include <iostream>
#include<queue>
#include<stdio.h>
#include<string.h>
#include<iomanip>
using namespace std;
struct Tree
{
int parent;
int weight;
int order;
int code_lenth;
}a[100];
struct cmp{
bool operator ()(Tree &a,Tree &b){
return a.weight>b.weight;
}
};
int hash[200];
int main()
{
priority_queue<Tree,vector<Tree>,cmp >q;
string n;
while(getline(cin,n),n!="END")
{
int lenth=n.size();
int j=1;
memset(hash,0,sizeof(hash));
a[1].order=j;
a[1].weight=1;
hash[n[0]]=j;
for(int i=1;i<lenth;i++)
{
int k=hash[n[i]];
if(k)
a[k].weight++;
else
{
a[++j].weight=1;a[j].order=j;hash[n[i]]=j;
}
}
for(int i=1;i<=j;i++)
q.push(a[i]);
for(int i=j+1;i<=2*j-1;i++)
{
Tree temp;
Tree temp1;
Tree temp2;
temp1=q.top();
q.pop();
temp2=q.top();
q.pop();
a[temp1.order].parent=i;
a[temp2.order].parent=i;
temp.weight=temp1.weight+temp2.weight;
temp.order=i;
temp.parent=0;
a[i]=temp;
q.push(temp);
}
q.pop();
for(int i=1;i<=j;i++)
{
int sum=0;
int k=i;
while(a[k].parent)
{
sum++;
k=a[k].parent;
}
a[i].code_lenth=sum;
}
int sum_lenth=0;
for(int i=0;i<lenth;i++)
{
int k=hash[n[i]];
sum_lenth+=a[k].code_lenth;
}
if(j==1)
sum_lenth=lenth;
cout<<lenth*8<<" "<<sum_lenth<<" ";
cout<<fixed<<setprecision(1)<<(float)lenth*8/(float)sum_lenth<<endl;
}
return 0;
}