“std::thread::thread(const std::thread &)”: 尝试引用已删除的函数

    
class ThreadClass
{
public:
	//void SendUpdatePackage(int stationNum, int &nResult, string &szErrMsg, std::vector<sockaddr_in> &BSAddrVector);
	int Print(int stationnum)
	{
		return stationnum;
	}

private:
	//std::mutex m_SFTPMutex;
};

int main()
{
	std::vector<std::thread> sftpThreadVec;
	int nResult = 0;
	ThreadClass tc;
	for (int i = 0; i < nThreadNum; i++)
	{
		thread my_thread(&ThreadClass::Print, &tc, i);
		sftpThreadVec.push_back(my_thread);
	}
	for (auto &a : sftpThreadVec)
		a.join();
    
    return 0;
}

这里 报错 “std::thread::thread(const std::thread &)”: 尝试引用已删除的函数

查看 thread 源码看到下面这行

thread(const thread&) = delete;

这里是禁用了thread的拷贝构造

而 std::vector 和 std::map 都是要求 类型 必须包含拷贝构造函数

可以这样

	int nResult = 0;
	ThreadClass tc;

	std::thread thArr[4];
	for (int i = 0; i < 4; i++)
	{
		thArr[i] = std::thread(&ThreadClass::Print, &tc, i);
	}

	for (auto &a : thArr)
		a.join();

经验证，这样也可以

	vector<thread> thVec;
	for (int i = 0; i < nThreadNum; i++)
	{
		//sftpThreadArr[i] = thread(&ThreadClass::SendUpPkg, &tc, i, pMainDlg);
		thVec.push_back(thread(&ThreadClass::SendUpPkg, &tc, i, pMainDlg));
	}

这种写法会报错，先实例化一个 thread对象，然后把这个对象push_back进 vector 会报这个错误

	vector<thread> thVec;
	for (int i = 0; i < nThreadNum; i++)
	{
		//sftpThreadArr[i] = thread(&ThreadClass::SendUpPkg, &tc, i, pMainDlg);
		thread ts = thread(&ThreadClass::SendUpPkg, &tc, i, pMainDlg);
		thVec.push_back(ts);
	}