Nim博弈
解法和HDU1850相似:http://blog.youkuaiyun.com/qinmusiyan/article/details/7949557
#include<iostream>
#include<cstdio>
using namespace std;
const int N=200002;
int a[N];
int main()
{
int m,sum,s,i;
while(scanf("%d",&m)!=EOF&&m)
{
sum=0;
for(i=0;i<m;i++)
{
scanf("%d",&a[i]);
sum=sum^a[i];
}
if(sum==0) printf("No\n");
else
{
printf("Yes\n");
for(i=0;i<m;i++)
{
s=sum^a[i];
if(s<a[i])
printf("%d %d\n",a[i],s);
}
}
}
return 0;
}