C primer plus 第十章练习11：

最新推荐文章于 2023-09-06 18:04:33 发布

原创最新推荐文章于 2023-09-06 18:04:33 发布 · 236 阅读

0 ·

CC 4.0 BY-SA版权

练习题专栏收录该内容

45 篇文章

订阅专栏

本文展示了一个使用C语言编写的程序，该程序通过函数化改进了原始的降雨量统计数据展示方式，实现了按年和按月显示平均降雨量的功能。

摘要生成于 C知道，由 DeepSeek-R1 满血版支持，前往体验 >

/*
=======================================================================
    重写程序清单10.7的程序rain, main()中的主要功能改为由函数来执行。
=======================================================================
*/

#include <stdio.h>
#define MONTHS 12
#define YEARS 5
void nian_p(int years, int month, float rain[][12]);
void yue_p(int years, int month, float rain[][12]);
int main(void)
{
    // 把数组初始化为2000年到2005年的降水量数据
    const float rain[YEARS][MONTHS] = {
        { 4.3,4.3,4.3,3.0,2.0,1.2,0.2,0.2,0.4,2.4,3.5,6.6 },
        { 8.5,8.2,1.22,1.6,2.4,0.0,5.2,0.9,0.3,0.9,1.4,7.3 },
        { 9.1,8.5,6.7,4.3,2.1,0.8,0.2,0.2,1.1,2.3,6.1,8.4 },
        { 7.2,9.9,8.4,3.3,1.2,0.8,0.4,0.0,0.6,1.7,4.3,6.2 },
        { 7.6,5.6,3.8,2.8,3.8,0.2,0.0,0.0,0.0,1.3,2.6,5.2 }
    };

    nian_p(YEARS, MONTHS, rain);
    yue_p(YEARS, MONTHS, rain);
    printf("\nDone!\n");
    return 0;
}

void nian_p(int years, int months, float rain[][12])
{
    float total = 0.0;
    float subtot = 0.0;
    printf(" YEAR   RAINFALL   (inches)  \n");
    for (int year = 0; year < years; year++)
    {
        for (int month = 0; month < months; month++)
            subtot += rain[year][month];
        printf("%5d %15.1f\n", 2000 + year, subtot);
        total += subtot;
    }
    printf("\nThe yearly average is %.1f inches.\n\n", total / YEARS);
}

void yue_p(int years, int months, float rain[][12])
{
    float subtot = 0.0;
    printf("MONTHLY AVERAGES: \n\n");
    printf(" Jan  Feb  Mar  Apr  May  Jun  Jul  Aug  Sep  Oct  Nov  Dec\n");
    for (int month = 0; month < months; month++)
    {
        for (int year = 0; year < years; year++)
            subtot += rain[year][month];
        printf("%4.1f ", subtot / YEARS);
    }
    printf("\n");
}