矩阵求逆引理(Matrix inversion lemma):
现有矩阵AA可以写为如下分块矩阵形式:
矩阵AA为 阶方阵,其中A11A11为nn阶非奇异方阵, 为mm阶非奇异方阵。那么可以得到: 和 (A22−A21A−111A12)(A22−A21A11−1A12)都是非奇异矩阵。
引理结论:
A−1=[A−111+A−111A12(A22−A21A−111A12)−1A21A−111−(A22−A21A−111A12)−1A21A−111−A−111A12(A22−A21A−111A12)−1(A22−A21A−111A12)−1]A−1=[A11−1+A11−1A12(A22−A21A11−1A12)−1A21A11−1−A11−1A12(A22−A21A11−1A12)−1−(A22−A21A11−1A12)−1A21A11−1(A22−A21A11−1A12)−1]
A−1=[(A11−A12A−122A21)−1−A−122A21(A11−A12