import time
import datetime
#time datetime使用方法备份
print(time.clock())
# 4.665275792443746e-07 返回处理器时间
print(time.process_time())
# 0.0780005
print(time.time())
# 1488616321.8451998 返回当前时间戳 <class 'float'>
print(time.ctime())
# Sat Mar 4 16:34:51 2017 格式化返回系统时间 <class 'str'>
print(time.ctime(887665))
# Sun Jan 11 14:34:25 1970
print(time.ctime(time.time() - 60*60*24 ))
# Fri Mar 3 16:39:17 2017 输出前一天
print(time.gmtime())
# time.struct_time(tm_year=2017, tm_mon=3, tm_mday=4, tm_hour=8, tm_min=41, tm_sec=32, tm_wday=5, tm_yday=63, tm_isdst=0)
# <class 'time.struct_time'> 格林尼治时间
print(time.localtime())
# time.struct_time(tm_year=2017, tm_mon=3, tm_mday=4, tm_hour=16, tm_min=43, tm_sec=43, tm_wday=5, tm_yday=63, tm_isdst=0)
# <class 'time.struct_time'> 当地时间
# !!此时时间格式为struct_time
print(time.mktime(time.localtime()))
# 1488617178.0
# 将struct_time时间转化为float格式的时间
print(time.strftime("%Y-%m-%d %H:%M:%S",time.localtime(time.time() - 60*60*24)))
# 2017-03-03 16:59:15
# 将struct_time转化为字符串类型的时间
# 首先:time.time() 为float格式 time.localtime() 的输入格式即为float,输出格式为struct_time
# time.strftime 又将struct_time 转化为字符串输出格式
print(time.strptime('2017-03-03 16:59:15',"%Y-%m-%d %H:%M:%S"))
# time.struct_time(tm_year=2017, tm_mon=3, tm_mday=3, tm_hour=16, tm_min=59, tm_sec=15, tm_wday=4, tm_yday=62, tm_isdst=-1)
# 与strftime相反,输入为字符串格式,按照格式对应的字段转化为struct_time格式
# '2017-03-03 16:59:15'与"%Y-%m-%d %H:%M:%S"是一一对应的。
----------
# datetime
print(datetime.date.today(),type(datetime.date.today()))
# 2017-03-04 <class 'datetime.date'>
# 当前日期
print(datetime.date.fromtimestamp(time.time() - 60*60*24))
# 2017-03-03
# 将float格式的时间戳转化为<class 'datetime.date'>格式
current_time = datetime.datetime.now()
print(current_time)
# 2017-03-04 17:20:41.851214 当前时间
print(current_time.timetuple())
# time.struct_time(tm_year=2017, tm_mon=3, tm_mday=4, tm_hour=17, tm_min=21, tm_sec=42, tm_wday=5, tm_yday=63, tm_isdst=-1)
# 将<class 'datetime.date'> 转化为 <class 'time.struct_time'>
print(current_time.replace(2012))
# 2012-03-04 17:29:53.446764
# 替换时间并输出
newtime = datetime.datetime.now() - datetime.timedelta(days=3)
print(datetime.datetime.now(),'\t',newtime)
# 2017-03-04 17:32:47.736732 2017-03-01 17:32:47.736732
# days=3 为3天时间 -号则表示3天前