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最新推荐文章于 2019-11-17 08:38:54 发布

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Sum Problem

Time Limit: 1000/500 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)
Total Submission(s): 479528 Accepted Submission(s): 121261

Problem Description

Hey, welcome to HDOJ(Hangzhou Dianzi University Online Judge).

In this problem, your task is to calculate SUM(n) = 1 + 2 + 3 + ... + n.

Input

The input will consist of a series of integers n, one integer per line.

Output

For each case, output SUM(n) in one line, followed by a blank line. You may assume the result will be in the range of 32-bit signed integer.

Sample Input

1
100

Sample Output

1

5050

这个题的题意是，给你一个数n，然后输出从1加到n的总和

大概的考察点就是for循环

#include<stdio.h>

int main()
{
    int n,a;
    while (scanf("%d", &n) != EOF)
    {
        int sum = 0;
        for (a = 0; a <= n; a++)
        {
            sum = sum+a;
        }
        printf("%d\n\n",sum);
    }
    return 0;
}